Answer:
120.0 mL.
Explanation:
We suppose that the initial W% of methanol is 100.0 %
∴ (W%V) before dilution = (W%V) after dilution.
W% before dilution = 100.0 %, V before dilution = 18.0 mL.
W% after dilution = 15.0 %, V after dilution = ??? mL.
∴ V after dilution = (W%V) before dilution/W% after dilution = (100.0 %)(18.0 mL)/(15.0%) = 120.0 mL.