Answer: OPTION C.
Step-by-step explanation:
By definition:
[tex]a^{1/n}=\sqrt[n]{a}[/tex]
You must descompose the numbers 160 and 243 into their prime factor:
[tex]160=2*2*2*2*2*5=2^{5}*5[/tex]
[tex]243=3*3*3*3*3=3^{5}[/tex]
Simplify the expression, then you obtain the following result:
[tex]\sqrt[5]{2^{5}*5*3^{5}}=2*3\sqrt[5]{5}=6\sqrt[5]{5}[/tex]
The answer is the option C.
