Answer:
[tex]The\: value \:of\: the\: first\: number\:is\:9[/tex]
Step-by-step explanation:
[tex]We\:have\:a\:system\:of\:equation:\\\left \{ {{x+y=39} \atop {3x+3=y}} \right. \\\Leftrightarrow \left \{ {{39-x=y} \atop {3x+3=39-x}} \right. \\\Leftrightarrow \left \{ {{39-x=y} \atop {4x=36}} \right. \\\Leftrightarrow \left \{ {{y=39-9} \atop {x=9}} \right. \\\Leftrightarrow \left \{ {{y=30} \atop {x=9}} \right. \\\Rightarrow x=9[/tex]
Answer with Step-by-step explanation:
The sum of two numbers is 39.
Let x represent the first number and let y represent the second number.
⇒ x+y=39
The second number is 3 more than three times the first number.
⇒ y=3x+3
Putting y=3x+3 in x+y=39
⇒ x+3x+3=39
⇒ 4x=39-3
⇒ 4x=36
Dividing both sides by 4, we get
x=9
Hence, Value of first number is:
9
