Determine which postulate or theorem can be used to prove that ABC=DCB

Answer with explanation:
In Δ ABC and ΔD BC
∠A=∠D-------Given
∠ABC=∠DCB-------Each being 90° given in the Diagram.
Side, BC is Common.
⇒⇒Δ ABC ≅ ΔD BC-------[AAS]
When two triangles are congruent , their areas are equal.
So, Area(ABC)=Area (DCB)
Option B :⇒ A AS
Answer:AAS is the correct answer ( apex)
Step-by-step explanation: