Question

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Answer 1

Answer:

D) $y=(x-3)^2-3$

Step-by-step explanation:

The first step is to find the vertex.

Start with getting your coefficients:

a = 1, b = -6, c = 6

plug them into the equation $x = -b/2a$

$6/2$

$x = 3$

Plug that back into the original equation to get y = -3

The vertex is going to be (3, -3)

The equation for Vertex Form is given by $f (x) = a(x - h)^2 + k$

(a) being the coefficient in front of the $x^2$

(h) being the first point on the vertex   (h,k) ({3},-3)

(k) being the second point on the vertex    (h,k) (3,{-3})

$y=(x-3)^2-3$

Answer 2

Answer:

d  y = (x-3) ^2 -3

Step-by-step explanation:

y = x^2 -6x+6

Complete the square to help find the vertex form

b= -6

b^2/2 = (-6/2) ^2 = (-3)^2 =9

We need to add 9  (and then subtract 9)

y = x^2 -6x +9+6 -9

y = (x^2 -6x +9)-3

We know that (x-b/2) ^2 is what we have now

y = (x-3) ^2 -3