Answer:
The zeros are -2, -1 and 2.
Step-by-step explanation:
I will assume that it is:
x^3 + x^2 - 4x - 4 = 0
Looks like x = -1 might be a root:
(-1)^3 + (-1)^2 - 4(-1) - 4
= - 1 + 1 + 4 - 4 = 0
So x = -1 is one zero.
As x = -1 is a zero then (x + 1) must be a factor of the expression so we divide:-
x + 1 ( x^3 + x^2 - 4x - 4 ( x^2 - 4 <------- The quotient
x^3 + x^2
-4x - 4
-4x - 4
So we have (x + 1)(x^2 - 4) = 0
(x + 1)(x - 2)(x + 2) = 0
Therefore the zeroes are -1,2 and -2,
