Question

The midpoint of EF is point P at (−6,−2). If point E is at (2,−4), what are the coordinates of point F?
A) (−14,0)
B) (−10,−8)
C) (−5,3)
D) (−2,−3)

Answer 1

Answer:

Option A is correct answer.

Step-by-step explanation:

Midpoint formula is given by

        x = $\frac{x_{1} +x_{2}}{2}$

         y = $\frac{y_{1} +y_{2}}{2}$

         Here E = (2,-4)

so x1 = 2 and y1= -4

 x = -6 and y = -2  are given

therefore using above mid point formula

-6 = $\frac{2 +x_{2}}{2}$

-6X2 = 2+x2

-12 = 2+x2

x2 = -12-2 = -14

Likewise

-2   = $\frac{y_{1} +y_{2}}{2}$

-2X2 =  -4 +y2

-4 = -4 +y2

y2 = 0

therefore Coordinate for point F will be (-14,0)