The value of x in the solution for this system of equations is -1.
Given the following system of equations:
- [tex]6x-y=4[/tex] ....equation 1.
- [tex]y=4x+2[/tex] ....equation 2.
To determine the value of x in the solution for this system of equations, we would use the substitution method:
In order to find a solution, we would substitute one of the equations into the other equation.
Substituting eqn. 2 into eqn. 1, we have:
[tex]6x-(4x+2)=4\\\\6x-4x-2+4=0\\\\2x+2=0\\\\2x=-2\\\\x=\frac{-2}{2}[/tex]
x = -1
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