What is the area of the triangle in this coordinate plane?

Answer:
[tex]49.0\:units^2[/tex]
Step-by-step explanation:
The area of a triangle can be found using the formula;
[tex]Area=\frac{1}{2}bh[/tex]
Observe that each box is 1 unit.
This implies that;
[tex]h=|15-1|=14\: units[/tex] is the height of the triangle.
[tex]b=|7-0|=7\: units[/tex] is the base of the triangle.
We plug these values into the formula to get;
[tex]Area=\frac{1}{2}(7)(14)[/tex]
[tex]Area=7\times7[/tex]
The area is [tex]49.0\:units^2[/tex]
Answer:
Last option is correct answer.
The area of triangle = 49 square units
Step-by-step explanation:
Formula:-
Area of triangle
Area A = bh/2
b - Base of triangle
h - Height of triangle
It is given a right angled triangle.
To find the base and height of triangle
From the figure we get the base of triangle, b = 7 units
Height of triangle, h = 15 - 1 = 14 units
To find the area of triangle
b = 7 units. h = 14 units
A = bh/2 = (7 * 14)/2 = 49 square units.
Therefore the area of triangle = 49 square units