Answer: The state with the second lowest population has the lowest population density.
Step-by-step explanation:
Since, Density = Population / Area
The population of state A = 1,055,173
Its area = 2677 square km
Thus, the density of state A = [tex]\frac{1055173}{2677}[/tex] = 394.162495,
The population of state B = 1,333,089
Its area = 36,418 square km
Thus, the density of state B = [tex]\frac{1,333,089}{36,418}[/tex] = 36.6052227,
The population of state C = 3,596,677
Its area = 5543 square km
Thus, the density of state C = [tex]\frac{3,596,677}{5543}[/tex] = 648.868302,
The population of state D =6,745,408
Its area = 10555 square km
Thus, the density of state D = [tex]\frac{6,745,408}{10555}[/tex] = 639.072288,
Since, by the above explanation,
The state in increasing order of the populations,
State A < State B < State C < State D,
Also, the state in increasing order of density,
State B < State A < State D < State C
⇒ Second option is correct.
