Answer:
Choice d is correct.
Step-by-step explanation:
We have the given function :
[tex]\lim_{x \to \6} x-3/x^{2} -9[/tex]
We have to find the limit.
First, simplify the denominator of function.
x²-9 = (x-3)(x+3)
Put this simplification in the function we get,
[tex]\lim_{x \to \6} x-3/(x-3)(x+3)[/tex]
finally we simplify the function we get,
[tex]\lim_{x \to \6} 1/x+3[/tex]
Apply the limit to the function we get,
[tex]\lim_{x \to \6} 1/x+3[/tex] = 1/9 = 0.1111111
Choice d is correct.
