Question

The circuit below shows two outdoor lights, run by a battery. Three amps of current leave the battery .Explain how the current splits to go through both light bulbs. Be as specific as you can.

Answer 1

Here two light bulbs are connected to a battery in parallel with the battery

So here the two bulbs will have same potential difference across them

Now we can see that both bulbs are identical and they have same resistance

So here we can say by ohm's law

$i = \frac{V}{R}$

here V = potential difference across the bulb

R = resistance of the bulb

since both the quantities are same for bulb i.e. potential difference as well as resistance both are same so current must be same in both bulbs

So total current will divide equally in both bulbs

So here current in each bulb will be half of total current

$i = 1.5 A$ in each bulb