Question

What is the value of h when the function is converted to vertex form?

Answer 1

Answer: h=7

Step-by-step explanation:

By definition the function in vertex form is:

 $f(x)=a(x-h)^{2}+k$

Where (h,k) is the vertex of the parabola.

You must group the terms that contain the same variable in the function:

$f(x)=(x^{2}-14x)+29$

Complete the square as following:

$f(x)=(x^{2}-14x+49)+29-49$

Now you must rewrite it as following:

 $f(x)=(x-7)^{2}-20$

Then:

h=7

Answer 2

Answer:

The value of h is 7.

Step-by-step explanation:

The given function is

$p(x)=x^2-14x+29$

where $a=1,b=-14,c=29$

The h-value of the vertex can be calculated with the formula;

$h=-\frac{b}{2a}$

We substitute the necessary values to obtain;

$h=-\frac{-14}{2(1)}$

Simplify to get;

$h=7$