Respuesta :

Answer:

[tex]f(x)=-\frac{1}{3}(x-2)^2+4[/tex],

Step-by-step explanation:

The function of the graph can be written in the vertex form as

[tex]f(x)=a(x-h)^2+k[/tex], where V(h,k)=V(2,4) is the vertex of the quadratic function.

We substitute the value to obtain;

[tex]f(x)=a(x-2)^2+4[/tex],

The point (5,1) lies on the graph so we use it to determine the value of a.

[tex]1=a(5-2)^2+4[/tex],

[tex]1-4=a(3)^2[/tex],

[tex]-3=9a[/tex],

[tex]a=-\frac{1}{3}[/tex]

The required equation is

[tex]f(x)=-\frac{1}{3}(x-2)^2+4[/tex],

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