The distance between two real numbers [tex]x,y[/tex] is the absolute value of their difference, [tex]|x-y|[/tex]. So the statement "all [tex]x[/tex] that are 1/4 away from -6" is captured in the equation
[tex]|x-(-6)|=\dfrac14[/tex]
or
[tex]|x+6|=\dfrac14[/tex]
To solve, you can use the definition of absolute value: if [tex]x[/tex] is not negative, then [tex]|x|=x[/tex]; otherwise, [tex]|x|=-x[/tex].
So there are two cases to consider:
1. Suppose [tex]x+6\ge0[/tex]. Then [tex]|x+6|=x+6[/tex], and the equation reduces to
[tex]x+6=\dfrac14\implies x=-\dfrac{23}4[/tex]
2. Suppose [tex]x+6<0[/tex]. Then [tex]|x+6|=-(x+6)=-x-6[/tex] and
[tex]-x-6=\dfrac14\implies x=-\dfrac{25}4[/tex]
[tex]-6=-\dfrac{24}4[/tex], so the two solutions we found are correct because both [tex]-\dfrac{23}4[/tex] and [tex]-\dfrac{25}4[/tex] are indeed 1/4 away from -6.
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For the question regarding inequality, you know that the absolute value must return a non-negative number. In other words, there is no [tex]x[/tex] such that [tex]|x|<0[/tex].