Answer:
[tex]\frac{x+2}{x+5}[/tex]
Step-by-step explanation:
Factorise the numerator and denominator
x² - x - 6 = (x - 3)(x + 2)
x² + 2x - 15 = (x - 3)(x + 5)
Hence
= [tex]\frac{(x-3)(x+2)}{(x-3)(x+5)}[/tex]
Cancel the factor (x - 3) on the numerator/ denominator leaving
[tex]\frac{x+2}{x+5}[/tex] ← equivalent expression