Answer:
The equation of the line in slope-intercept form is y =3x+12
Step-by-step explanation:
The first step is to rewrite the equation of the line in the slope-intercept form in order to identify the slope of the line. The re-written equation is;
y = 3x-7.
This implies that the slope of the line is 3. Since the two lines are parallel they they will have equal slope of 3. The slope-intercept form of the equation of this line will be;
y =3x+c.
Since the line passes through (-5, -3), substitute x with -5 and y with -3 to solve for c;
-3 =3(-5)+c.
We find c =12 and the equation of the line becomes;
y =3x+12.
Answer:
y = 3x+12 is the line parallel to 3x-y-7=0 that passes through point (-5, -3).
Step-by-step explanation:
We have given an equation:
3x-y-7=0
above equation in standard form:
y = 3x-7 (eq I)
We have to the line parallel to to 3x-y-7=0 that passes through point (-5, -3).
The slope of (eq I) is m = 3.
The parallel lines have same slopes.
So, the line parallel to given lines has slope m = 3.
The general form of slope-point form of equation is:
y = m(x) +c (eg II)
putting y= -3 , x= -5 and m = 3 in above equation we get,
-3 = 3(-5)+c
-3=-15+c
c = -3+15
c =12
Putting the value of c and m=3 in ( eq II) weget,
y = 3x+12 is the line parallel to 3x-y-7=0 that passes through point (-5, -3).
