The perfect square is (x + 13)² and the value of c is 169 for the quadratic function x² + 26x + c after using perfect square trinomial.
What is a quadratic equation ?
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]
The question is incomplete:
The question is: Find the value of c that will make x² + 26x + c a perfect square trinomial.
We have a quadratic function:
= x² + 26x + c
= x² + 26x + c + 13²—13²
= (x + 13)² + c—169
= (x + 13)² + (c—169)
c—169 = 0 (to make perfect square equate to zero)
c = 169
Thus, the perfect square is (x + 13)² and the value of c is 169 for the quadratic function x² + 26x + c after using perfect square trinomial.
Learn more about quadratic equations here:
brainly.com/question/2263981
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