Respuesta :
Answer:
Equation the ellipse is [tex]\frac{x^{2}}{25}+\frac{y^{2}}{9}=1[/tex]
Step-by-step explanation:
In the question vertices of an ellipse are given as (1, 5) and (1, -5).Co vertex is (3, 0).
We know the standard form of ellipse is [tex]\frac{x^{2} }{a^{2} } +\frac{y^{2} }{b^{2} } = 1[/tex]
If a > b then ellipse is horizontal
and the origin is (0, 0)
Given from the question a = 5 and b = 3
Since a > b therefore ellipse is horizontal
So the equation of ellipse will be
[tex]\frac{x^{2}}{5^{2}}+\frac{y^{2}}{3^{2}}=1[/tex]
[tex]\frac{x^{2}}{25}+\frac{y^{2}}{9}=1[/tex]
Therefore the answer is [tex]\frac{x^{2}}{25}+\frac{y^{2}}{9}=1[/tex]
Answer: B. [tex]\frac{(x-1)^{2} }{2^{2} } +\frac{y^{2} }{5^{2} } =1[/tex]
Step-by-step explanation: I got this right on Edmentum.
