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Select the correct answer.
If the vertices of an ellipse are at (1, 5) and (1, -5) and (3, 0) is a point on the ellipse, what is the ellipse equation?



Respuesta :

Answer:

Equation the ellipse is [tex]\frac{x^{2}}{25}+\frac{y^{2}}{9}=1[/tex]

Step-by-step explanation:

In the question vertices of an ellipse are given as (1, 5) and (1, -5).Co vertex is (3, 0).

We know the standard form of ellipse is [tex]\frac{x^{2} }{a^{2} } +\frac{y^{2} }{b^{2} } = 1[/tex]

If a > b then ellipse is horizontal

and the origin is (0, 0)

Given from the question a = 5 and b = 3

Since a > b therefore ellipse is horizontal

So the equation of ellipse will be

[tex]\frac{x^{2}}{5^{2}}+\frac{y^{2}}{3^{2}}=1[/tex]

[tex]\frac{x^{2}}{25}+\frac{y^{2}}{9}=1[/tex]

Therefore the answer is [tex]\frac{x^{2}}{25}+\frac{y^{2}}{9}=1[/tex]

Answer: B. [tex]\frac{(x-1)^{2} }{2^{2} } +\frac{y^{2} }{5^{2} } =1[/tex]

Step-by-step explanation: I got this right on Edmentum.

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