Question

Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2. What is the displacement of Andy’s car after 30.0 seconds?

Answer 1

1200 m/s squared, assuming the initial velocity is 0.

Answer 2

Answer:

7200 m

Explanation:

This problem is an example of an uniformly accelerated motion, in which the acceleration remains constant. As such, the formula for the displacement is:

D(t) = D₀ + v₀*t + 0.5*a*t²

Where D₀ is the initial displacement, v₀ is the initial velocity (in this case it's 0 m/s), a is the aceleration (8 m/s²) and t is the time, in seconds.

Using a t=30.0 s, we're left with:

D(t) = 0 m + 0 m/s * 30.0 s + 0.5 * 8.00 m/s² * (30.0 s)²

D(t) =  0.5 * 8.00 m/s² * (30.0 s)²

D(t) = 7200 m