Question

What is the area of this polygon? Enter your answer in the box. units²
5-sided polygon on a coordinate plane with points M, V, E, D, and R. Point M is at (negative 5, 2), point V is at (negative 2, 3), point E is at (3, 3), point D is at (3, negative 3), and point R is at (negative 2, negative 3).

Answer 1

Answer:

The area of the polygon is $39\:units^2$

Step-by-step explanation:

Sketch the polygon to obtain the figure in the attachment.

The polygon can then be divided into a rectangle and a triangle.

The area of the polygon

$=|VE|\times |DE|+\frac{1}{2}\times |DE|\times |AM|$

We use the absolute value method to find the lengths

$=|3--2|\times |3--3|+\frac{1}{2}\times|3--3|\times |5-2|$

$=5\times 6+\frac{1}{2}\times 6\times 2$

$=30+9$

$=39\:units^2$

Answer 2

This question based on the area of polygon. Therefore, the area of this polygon MVEDR I is $\bold{39\;units^{2} }$ .

Given:

A 5-sided polygon also known as pentagon on a coordinate plane with points M, V, E, D, and R.

Point M is at ( -5, 2), point V is at (-2, 3), point E is at (3, 3), point D is at (3, -3), and point R is at (-2, -3).

We need to determined the area of polygon MVEDR.

Sketch the polygon to obtain the figure in the attachment.

From figure, it is shown that, this polygon consists rectangle and triangle.

Thus, the formula of area of polygon is sum of  area of triangle and area of rectangle .

In mathematically, expressed as

$|VE| \times |DE| + \dfrac{1}{2} \times |DE| \times |AM|$

Now, find the absolute value of length. By using the formula we get,

$=|3-(-2)| \times |3-(-3)| + \dfrac{1}{2} \times |3-(-3)| \times |5-2|\\\\=5\times6+\dfrac{1}{2} \times 6 \times 3\\\\=30+9\\\\=39 \:units^{2}$

Therefore, the area of this polygon MVEDR I is $\bold{39\;units^{2} }$ .

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