Respuesta :

Answer:

Option 1. (-1, 1 ) is the correct option.

Step-by-step explanation:

The given polynomial function is

[tex]f(x) = 2x^{4}-x^{3}+x-2[/tex]

To find the real zeros of any polynomial we follow the procedure as below

First we find p/q where p represents the factors of constant term of the polynomial and q represents the factors of the coefficient of highest degree term of the expression.

So factors will be = p/q = ± factors of 2/ ± factors of 2

                                      = ±1, ±2/±1, ±2

So the probable factors are ±1, ±2

Now by putting the values of x in the polynomial [tex]f(x) = 2x^{4}-x^{3}+x-2[/tex]

For x = 1

f(x) = 2 - 1 + 1 - 2 = 0

Therefore (x-1) is a factor.

For x = -2

f(x) = 2×16 + 8 -2 -2 = 36

So its not the factor.

For x = -1

f(x) = 2 + 1 - 1 - 2 = 0

Therefore for x = -1 and x= 1 f(x) is zero.

ACCESS MORE