Look kid, this question has been up for 5 hours think its time to let it go......... hoped i helped. ✔verified✔
Answer:
Q5-- AQ=3
Q6---45°
Q7---90°
Q8---6
Step-by-step explanation:
∠PAQ=90°{Diagonals of rhombus bisects at 90°}
Applying Pythagoras theorem
AQ=3
Diagonals of rhombus are equal in length and they bisects each other
i.e. AP=AQ
∆APQ is an isoceles ∆
Applying Angle sum property of ∆
m∠APQ= 180°-90°/2
m∠APQ=45°
SIMILARLY m∠ANM and m∠ANP=45°
m∠MNP=m∠ANM + m∠ANP
m∠MNP=90°
PM=AP+PM
PM=6
