Question

(7*5*2 / 7*3)^(2) *(5^(0) / 2^(-3) * 2^(-9)=??? does it make sense to anyone?? please help...

Answer 1

evaluate
remember that x^0=1
and x^-m=1/(x^m)

simplify
PEMDAS
parenthasees exponentes mulitplciraon or diviosn additon or subtraction

parethasees first

inside to ut
lef to right
7*5*2/7*3
70/21
10/3

then in the next partnheasees
5^0/2^-3 times 2^-9
1/(1/2^3)(1/2^9)
1/(1/8)(1/512)
8/512
1/64

so now we have
(10/3)^2 times 1/64
100/9 times 1/64
100/576
25/144

you should group them better so it is easier to read

Answer 2

Yes so you want to use pemdas.

First parenthesis:
(5*2/3)^2 = (10/3)^2 = 100/9 * (1/1/8)*1/(2^9)) = 100/9*(8/512) = 100/9(1/64) = 25/144 = .17361