Question

Pls Help Me im in K12 and im having a hard time on this question bc i don't get it
Using the Two-Transversal Proportionality Corollary, what is the approximate value of J K?


A.10.6 cm

B.30.5 cm

C.6.7 cm

D.28.6 cm

Answer 1

Answer:

The approximated value of JK is 10.6 cm answer (A)

Step-by-step explanation:

∵ JI // KH // LG

∵ XI and XJ are two transversal

∴ $\frac{LK}{GH}=\frac{KJ}{HI}$

∵ LK = 18 cm , GH = 22 cm and HI = 13 cm

∴ $\frac{18}{22}=\frac{KJ}{13}$

∴ KJ = (13)(18) ÷ 22 = 10.6363 cm

∴ The approximated value of JK is 10.6 cm