If f(x) = x2 – 25 and g(x) = x – 5, what is the domain of (f/g)(x)
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Answer:
The domain is all real values except x = 5
Step-by-step explanation:
∵ f(x) = [tex]x^{2}-25[/tex]
∵ g(x) = x - 5
∵ [tex]\frac{f(x)}{g(x)}=\frac{x^{2}-25 }{x-5}[/tex]
The domain of it is all the values of x make [tex]\frac{f(x)}{g(x)}[/tex] is defined
∴ The denominator can not be zero
∵ x - 5 = 0⇒ means x = 5
∴ We can't use 5 as a value for x
∴ The domain of [tex]\frac{f(x)}{g(x)}[/tex] is all the real number except x = 5
Answer:
Choice A is correct answer.
Step-by-step explanation:
We have given two functions.
f(x) = x² – 25 and g(x) = x – 5
We have to find (f/g)(x).
The formula to find (f/g)(x) is:
(f/g)(x) = f(x) / g(x)
Putting given values in above formula, we have
(f/g)(x) = x²-25 / x-5
(f/g)(x) = (x-5)(x+5) / x-5
(f/g)(x) = x+5
Now, domain of above function is all real values of x.