Based on the diagram, what is sinA ?
Enter your answer as a fraction in the boxes.
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Answer:
sinA = [tex]\frac{a}{c}[/tex]
Step-by-step explanation:
sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{a}{c}[/tex]
For this case, we have that by definition:
[tex]Sine (x) = \frac {Cathet \ opposite \ to \ angle \ x} {Hypotenuse}[/tex]
In this case we are asked to find the expression as a function of angle A.
Observing the figure we have:
[tex]Sine (A) = \frac {a} {c}[/tex]
In an equivalent way we have:
[tex]Sine (A) = \frac {BC} {BA}[/tex]
ANswer:
[tex]Sine (A) = \frac {a} {c}\\Sine (A) = \frac {BC} {BA}[/tex]