Question

Write a quadratic equation with the root of 1/3 and -7/2

A-y=(x-3)(7x+2)
C-y=(3x-1)(2x+7)
D-y=(3x+1)(2x-7)

Answer 1

The answer is C-y=(3x-1)(7x+2)

Answer 2

Answer:

C  y = (3x - 1)(2x + 7).

Step-by-step explanation:

That would be y = (3x - 1)(2x + 7).

if we solve   (3x - 1)(2x + 7) = 0

(3x - 1)(2x + 7) = 0

3x - 1 = 0 or 2x + 7 = 0

x = 1/3 , -7/2.