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PLEASE HELP. A train is slowing down with an average acceleration of -5.0 m/s2. ( negative sign shows deceleration ). If it’s an initial velocity is 50 mi./s how far does a travel in 6 seconds?

Respuesta :

Answer: The train traveled 210 miles in 6 seconds of time duration.

Explanation:

The initial velocity of the train,u = 50 mile/s

Acceleration of the train ,a = [tex]-5.0 m/s^2[/tex]

Duration of time ,t = 6 seconds

Using second equation of motion :

[tex]s=ut+\frac{1}{2}at^2[/tex]

[tex]s=50 mile/s\times 6 s+\frac{1}{2}(-5.0 m/s^2)(6s)^2=210 miles[/tex]

The train traveled 210 miles in 6 seconds of time duration.

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