Question

What is the focus of the parabola?

y=−14x2−2x−2

Enter your answer in the boxes.

Answer 1

Answer:

Step-by-step explanation:

Given is a parabola

$y=-14x^2-2x-2$

Let us rewrite this in vertex form

$y=-14(x+\frac{1}{14})^2-\frac{27}{14}$

Hence vertex =$(\frac{-1}{14} ,\frac{-27}{14} )$

Axis of symmetry is

$x=-\frac{1}{14}$

a=$\frac{1}{(14)4} =\frac{1}{56}$

Hence focus would lie on the line of symmetry at a distance of a from vertex

So focus =$(-\frac{1}{14} ,-\frac{27}{14} -\frac{1}{56} )\\=(-\frac{1}{14} , -\frac{109}{56} )$

Answer 2

Answer:

If this is for k12 I took the test and the right answer was (-4, 1)

Step-by-step explanation: