Question

A factory is responsible for filling tin cans with soup.
The volume of soup to be canned is 1470 litres to the nearest 5 litres.
The tins have a volume of 288.2ml correct to one decimal place.
Calculate the maximum number of full tins that could be produced.

Answer 1

you have to find the upper and lower bound of each number.

lb of 1470 litres (nearest 5 litres) = 1465

ub = 1475

lb of 288.2ml (one dp) = 288.15

ub = 288.25

to find the no of full tins you have to divide the volume of the soup by the volume of the tins

to find the MAXIMUM volume you have to try and get the largest number possible so you have to divide your UPPER BOUND by your LOWER BOUND as this will give u the largest value possible.

UB/LB

= 1475/ 288.15

= 5.118861704

round down (FULL tins)

= 5 tins