Question

Given A(-12,5) and B(12,29) find the point that divides the line segment AB three-eighths of the way from A to B

Answer 1

Answer:

$\text{The coordinates are}(\frac{-60}{11},\frac{127}{11})$

Step-by-step explanation:

Given two points A(-12,5) and B(12,29). We have to find the point that divides the line segment AB three-eighths of the way from A to B.

By section formula, when a point C divides a segment AB in the ratio m:n, then the coordinates of point C are

$C(\frac{(mx_2+nx_1)}{(m+n)},\frac{(my_2+ny_1)}{(m+n)})$

⇒ $C(\frac{(3(12)+8(-12))}{(3+8)},\frac{(3(29)+8(5))}{(3+8)})$

⇒ $C(\frac{(36-96)}{11)},\frac{(87+40)}{(11)})$

⇒  $C(\frac{-60}{11},\frac{127}{11})$

Hence, the coordinates of point C that divides the line segment AB three eighths of the way from A to B are $(\frac{-60}{11},\frac{127}{11})$