parallel lines have exactly the same slope.
so this line will have the same slope as y = 4x - 1, so
[tex]\bf y=\stackrel{\downarrow }{4}x-1\qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
so, we're really then, looking for the equation of a line that has a slope of 4, and runs through -3, 7.
[tex]\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{7})~\hspace{10em} slope = m\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=4[x-(-3)]\implies y-7=4(x+3) \\\\\\ y-7=4x+12\implies y=4x+19[/tex]
