Answer : The amount of heat absorbed are, 258485.5 J
Solution :
Formula used :
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
where,
Q = heat gained = ?
m = mass of water = 650 g
c = specific heat of water = [tex]4.186J/g^oC[/tex]
[tex]\Delta T=\text{Change in temperature}[/tex]
[tex]T_{final}[/tex] = final temperature = [tex]100^oC[/tex]
[tex]T_{initial}[/tex] = initial temperature = [tex]5^oC[/tex]
Now put all the given values in the above formula, we get the final temperature of copper.
[tex]Q=650g\times 4.186J/g^oC\times (100-5)^oC[/tex]
[tex]Q=258485.5J[/tex]
Therefore, the amount of heat absorbed are, 258485.5 J