Question

After t seconds, a ball tossed in the air from the ground level reaches a height of h feet given by the equation h = 144t-16t^2. After how many seconds will the ball hit the ground before rebounding?

Answer 1

Answer:

h(t) = 144·t - 16·t^2 = 16·t·(9 - t) = 0

9 - t = 0 --> t = 9

The ball will hit the ground after 9 seconds.

Answer 2

The ball will hit the ground before rebounding after 9 seconds .

How to Calculate time parameter from dependent variable equation ?

Given that a ball tossed in the air from the ground level reaches a height of h feet . The equation given for it is -

$h = 144t - 16t^{2}$  which is time dependent

We have to find the time t when the ball will hit the ground before rebounding.

Thus for this to happen , at the instant when the ball first touches the ground, the height of the ball is zero from the ground , just before rebounding.

Putting h = 0 in the above equation ,

   $144t - 16t^{2} = 0$

⇒ $16t^{2} = 144t$

⇒ $16t = 144$

∴   $t = 9$

Thus the ball will hit the ground after 9 seconds .

To learn more about parameterized equations, refer -

https://brainly.com/question/19790478

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