Since there is no friction on the ramp so there is no loss of energy in terms of frictional loss
So here we can use mechanical energy conservation law in this case
so here we will have
[tex]U_i = KE_f[/tex]
here we know that
[tex]U_i = mgh[/tex]
also we know that
[tex]K_f = \frac{1}{2}mv^2[/tex]
now we will have
[tex]mgh = \frac{1}{2}mv^2[/tex]
now by solving above equation we have
[tex]v = \sqrt{2gh}[/tex]
so here as we know all identical balls are released from same height so all balls must have same speed at the end