Question

How many molecules of sucrose C12H22O11 are there in 454 grams of sucrose

Answer 1

c(C12H22O11) = 342.3 g/mol

454 g / (342.3 g/mol) = 1.326 mol

1.326 mol * 6.022*10^23 molecules/mol = 7.985·10^23 molecules

Answer 2

Answer:

Explanation:

I mole of sucrose = 6.02 X 10²³ molecules

454 grams of sucrose = ?

To find the number of moles of sucrose in 454grams:

no of moles = mass/molarmass

mass = 454g

molar mass of sucrose C12H22O11 = (12x12) + (1x22) + (16x11)

                                                          =144+22+176

                                                          342g/mol

no. of moles = 454/342

                     = 1.33mole

since 1 mole of sucrose = 6.02 X 10²³ molecules

         1.33 mole of sucrose = 1.33 X 6.02 X 10²³

                                            = 8.01 X 10²³ molecules