Question

A gas in a balloon at constant pressure has a volume of 160 mL at -125*C. What is its volume at 29.0*C?

Answer 1

Answer:- 330 L

Solution:- At constant pressure, volume is directly proportional to the kelvin temperature.

$V_1T_2=V_2T_1$

where, $V_1$ is the initial volume at initial temperature $T_1$ and $V_2$ is the new volume at temperature $T_2$ .

From given info,

$V_1$ = 160 mL

$T_1$   = -125 + 273 = 148 K

$T_2$ = 29.0 + 273 = 302 K

$V_2$ = ?

Let's plug in the values and solve this for new volume.

$160mL(302K)=V_2(148K)$

On rearrangement:

$V_2=\frac{160mL(302K)}{148K}$

[tex]V_2] = 326 L

If we round the answer for two sig figs(as given in initial volume) then it will be 330 L.

So, the new volume of the balloon is 330 L.