Question

Rewrite the following quadratic functions in intercept or factored form. Show your work.

f(x) = 3x^2 - 12

Answer 1

Answer:

f(x) = 3(x+2)(x-2)

Step-by-step explanation:

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

$f(x) = 3x^2 - 12$

We can factorize the given function so taking the common factors out of it to get:

$f(x)=3x^2 - 12$

$f(x) = 3 (x^2 - 4)$

The term $(x^2-4)$ is in the form $a^2-b^2$ so it can further be factorized to give:

$f(x) = 3 (x+2)(x-2)$

Therefore, the factored form of the given quadratic function is f(x) = 3(x+2)(x-2).

Answer 2

Answer:

3(x-2)(x+2)

Step-by-step explanation:

Given equation is :

f(x) = 3x²-12

We have to rewrite the given function in factored or intercept form.

Since, we know that 3 and 12 are multiples of 3.

taking 3 as common , we get

f(x) = 3(x²-4)

using differernce formula in above equation , we get

a²-b² = (a-b)(a+b)

f(x) = 3(x-2)(x+2)

Hence, the given factors are 3,(x-2) and (x+2).