Question

A female car has two recessive genes for long fur (s) and a male cat has two dominant genes for short fur (SS). What is the likehood the two cats produce a kitten with short fur?

Answer 1

There is a 100 percent chance that the cats will produce a kitten with short fur.

Answer 2

Answer:

100% or 1 probability

Explanation:

This is a typical monohybrid cross involving a single gene; a gene coding for fur length in cats. The allele coding for short fur (S) is dominant over the allele coding for long fur (s).

In a cross involving a female cat which is homozygous recessive (ss) i.e. (having same recessive allele and phenotypically long furred) and a male cat which is homozygous dominant (SS) i.e. (having same dominant allele and phenotypically short furred), all offsprings (kittens) in the F1 generation will be phenotypically short-furred but genotypically heterozygous (Ss). (See attached image).

Since all offsprings will be phenotypically short-furred, therefore, the likelihood or probability of producing a short furred kitten is 100% or 1.