When a 757 passenger jet begins its descent to the Ronald Reagan National Airport in Washington, D.C., it is 3900 feet from the ground. Its angle of descent is 6 degrees.

How far must the plane fly to reach the run way?
A. 37,106 ft
B. 37,310.4 ft
C. 23,456.6 ft
D 2,492.7 ft

Respuesta :

Answer:

Option A. 37106 ft.

Step-by-step explanation:

Given: An 757 passenger jet at the height of 3900 feet from the ground means vertical height = 3900 feet.

Angle of descent to the airport in Washington,D.C. is 6 degrees.

To find: Horizontal distance the plane will cover to reach the run way.

Solution: As we know tan ∅  = [tex]\frac{Height}{Base}[/tex]

Then tan 6° = [tex]\frac{3900}{x}[/tex]

0.105 = [tex]\frac{3900}{x}[/tex]

x = [tex]\frac{3900}{.105}[/tex]

x = 37106 ft

Answer:

D

Step-by-step explanation: