When the car starts moving it acquires kinetic energy.
For this problem the formula of kinetic energy is:
[tex]\frac{1}{2}mv^2[/tex]
Where m is the mass of the car = 850kg, and v is the speed of the car.
If we consider insignificant the energy lost by friction with soil and air we can propose the following equation:
Applied energy = Kinetic energy acquired by the car.
[tex]13000\ J = \frac{1}{2}mv^2\\\\13000\ J = \frac{1}{2}(850)v^2\\\\\frac{13000(2)}{850} = v^2\\\\v = \sqrt{\frac{13000(2)}{850}}\\\\v = 5.531 m/s[/tex]
The velocity is 5.531 m/s