Question

Find the value of x to the nearest tenth.

Answer 1

Answer:

Step-by-step explanation:

a^2+b^2=c^2

So(1/2)x^2+6^2=12^2

1/2(x^2)+36=144

1/2(x)=sqrt of 108

sqrt of 108=10.39

So, x=10.39*2=20.78

Answer 2

Answer: 20.8 units

Step-by-step explanation:

From the given picture, it can be seen that the radius of the circle  r= 12 units

The distance from chord to the center of the circle a= 6 units

We know that in a circle , the perpendicular line from the center of the circle bisect the chord.

Using Pythagorean theorem of right triangle , we get

$r^2=a^2+(\dfrac{x}{2})^2\\\\\Rightarrow\ 12^2=6^2+(\dfrac{x}{2})^2\\\\\Rightarrow\ (\dfrac{x}{2})^2=144-36\\\\\Rightarrow\ (\dfrac{x}{2})^2=108\\\\\Rightarrow\ \dfrac{x}{2}=10.3923048454\approx10.4\\\\\Rightarrow\ x=20.8$

The value of x = 20.8 units.