Answer:
width of the rectangle=x=4in and length of the rectangle=11in
Step-by-step explanation:
Let the width of the rectangle be x, then according to the question, length is one less than three times its width that is l=3x-1.
Now, width=b=x and length=l=3x-1, thus
Perimeter of the rectangle= 2(l+b)
⇒[tex]30=2(3x-1+x)[/tex]
⇒[tex]15=(3x-1+x)[/tex]
⇒[tex]15=4x-1[/tex]
⇒[tex]16=4x[/tex]
⇒[tex]x=4in[/tex]
Thus, width of the rectangle=x=4in and length of the rectangle=l=3x-1=3(4)-1=12-1=11in.