Question

Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how many logs (y) she needs to keep the fire burning for 18 hours. She assumes all the logs are the same how many logs does Tressa need to make a 18 hour fire?

Answer 1

Answer:

Answer :27 logs

Step-by-step explanation:

Well if we have the function y=6/4x, since it takes 6/4 log to keep burning for 1 hour, we just plug in x as 18, and we can simplify that to 27.

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Answer 2

Answer: 27 logs

Step-by-step explanation:

Given : Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs.

From the given situation , it is clear that the number of log and time for fire burning are directly proportional.

The equation for direct variation :-

$\dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}$

Put , $x_1=4, y_1=6,\ \ x_2=18,y_2=y$, where y is the number of logs need to keep the fire burning for 18 hours.

$\dfrac{4}{6}=\dfrac{18}{y}\\\\\Rightarrow\ y=\dfrac{6\times18}{4}=27$

Hence,she needs 27 logs to keep the fire burning for 18 hours.