Answer:
y² + y + [tex]\frac{1}{4}[/tex] = (y + [tex]\frac{1}{2}[/tex])²
Step-by-step explanation:
In most cases, we can factor a polynomial, or quadratic, by looking at the factors of the last term. In this case, the last term is [tex]\frac{1}{4}[/tex]. When we factor a polynomial, we are looking for two expressions that when multiplied together using FOIL (forward-outside-inside-last) will give us the polynomial. For example: (a + b)(a + b) or (a+ b)².
In order to get y² + y + [tex]\frac{1}{4}[/tex], we are looking for a 'c' value that will add up to '1' which is our 'b' value (ay² + by + c).
Since [tex]\frac{1}{2}*\frac{1}{2}=\frac{1}{4}and\frac{1}{2}+\frac{1}{2}=1[/tex]
Then, we can use [tex]\frac{1}{2}[/tex] as our factor for both expressions. Putting this together we get: (y + [tex]\frac{1}{2}[/tex])(y + [tex]\frac{1}{2}[/tex]) or (y + [tex]\frac{1}{2}[/tex])²