Respuesta :

MsRay

Answer:

y² + y + [tex]\frac{1}{4}[/tex] = (y + [tex]\frac{1}{2}[/tex])²

Step-by-step explanation:

In most cases, we can factor a polynomial, or quadratic, by looking at the factors of the last term.  In this case, the last term is [tex]\frac{1}{4}[/tex].  When we factor a polynomial, we are looking for two expressions that when multiplied together using FOIL (forward-outside-inside-last) will give us the polynomial.  For example: (a + b)(a + b) or (a+ b)².

In order to get y² + y + [tex]\frac{1}{4}[/tex], we are looking for a 'c' value that will add up to '1' which is our 'b' value (ay² + by + c).

Since [tex]\frac{1}{2}*\frac{1}{2}=\frac{1}{4}and\frac{1}{2}+\frac{1}{2}=1[/tex]

Then, we can use [tex]\frac{1}{2}[/tex] as our factor for both expressions.  Putting this together we get:  (y + [tex]\frac{1}{2}[/tex])(y + [tex]\frac{1}{2}[/tex]) or (y + [tex]\frac{1}{2}[/tex])²

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