Question

What is the value of 13x^-3y^-1 when x=-1 and y=4

Answer 1

Answer:

-49/4

Step-by-step explanation:

(13)(-1^-3)-(-3)(4^-1)

Negative exponents move the x and y to the denominator.

(13/-1)-(-3/4)= -12 1/4 = -49/4

Answer 2

Answer:

$-\frac{13}{4}$

Step-by-step explanation:

Given expression,

$13x^{-3}y^{-1}$

By using $a^m=\frac{1}{a^{-m}}$

$=\frac{13}{x^3y}$

We have, x = -1 and y = 4

By substituting the values,

$=\frac{13}{(-1)^3(4)}$

$=\frac{13}{-4}$

$=-\frac{13}{4}$

Hence, the value of given expression is $-\frac{13}{4}$.