Respuesta :

Answer:

[tex]\sqrt{\left(a+b\right)^{2}+c^{2}}[/tex]

Step-by-step explanation:

The distance between the line joining points A (-b, c) and C (a, o) will be the length of the diagonal of given trapezoid.

Now, [tex]x_{1} = - b,\ y_{1} = c\ and\ x_{2} = a, y_{2} = 0[/tex]

Now, using distance formula,

AC = [tex]\sqrt{\left (x_{2}-x_{1}\right )^{2}+\left (y_{2}-y_{1}\right )^{2}}[/tex]

AC = [tex]\sqrt{\left(a-(-b) \right)^{2}+\left(0-c\right)^{2}}[/tex]

AC = [tex]\sqrt{\left(a+b\right)^{2}+\left(-c\right)^{2}}[/tex]

AC = [tex]\sqrt{\left(a+b\right)^{2}+c^{2}}[/tex]

Therefore, the length of diagonal AC of trapezoid = [tex]\sqrt{\left(a+b\right)^{2}+c^{2}}[/tex]

So, option (4) is the right option.

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