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For each of the compounds below, show that the charges on the ions add up to zero.

A. KBr

B. CaO

C. Li(2)O

D. CaCl(2)

E. AlCl(3)

Respuesta :

A) Potassium Bromide KBr

KBr = K⁺Br⁻

Sum of Charges = (+1) + (-1) = 0

B) Calcium oxide CaO

CaO = Ca²⁺O²⁻

Sum of charges = (+2) + (-2) = 0

C) Lithium oxide Li2O

Li₂O = Li⁺O²⁻

Sum of charges = 2*(+1) + (-2) = 0

D) Calcium chloride CaCl2

CaCl₂ = Ca²⁺Cl⁻

sum of charges = (+2) + 2(-1) = 0

E) Aluminum chloride AlCl3

AlCl₃ = Al³⁺Cl⁻

Sum of charges = (+3) + 3(-1) = 0

Answer:

Explanation:

a.) KBr has 1 potassium ion with a charge +1 and 1

bromide ion with the charge -1.

b.) CaO has 1 calcium ion with the charge +2 and 1

oxide ion with the charge -2.

c.) Li2O has 2 Li ions with the charge +1 each and 1

oxide ion with the charge -2.

d.) CaCl2 has one calcium ion with the charge +2

and 2 chloride ions each with the charge -1.

e.) AlCl3 has 1 aluminum ion with the charge +3 and

3 chloride ions each with the charge -1.

hope this helps~ (plz mark brainliest Sam Dover)

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