Respuesta :
A) Potassium Bromide KBr
KBr = K⁺Br⁻
Sum of Charges = (+1) + (-1) = 0
B) Calcium oxide CaO
CaO = Ca²⁺O²⁻
Sum of charges = (+2) + (-2) = 0
C) Lithium oxide Li2O
Li₂O = Li⁺O²⁻
Sum of charges = 2*(+1) + (-2) = 0
D) Calcium chloride CaCl2
CaCl₂ = Ca²⁺Cl⁻
sum of charges = (+2) + 2(-1) = 0
E) Aluminum chloride AlCl3
AlCl₃ = Al³⁺Cl⁻
Sum of charges = (+3) + 3(-1) = 0
Answer:
Explanation:
a.) KBr has 1 potassium ion with a charge +1 and 1
bromide ion with the charge -1.
b.) CaO has 1 calcium ion with the charge +2 and 1
oxide ion with the charge -2.
c.) Li2O has 2 Li ions with the charge +1 each and 1
oxide ion with the charge -2.
d.) CaCl2 has one calcium ion with the charge +2
and 2 chloride ions each with the charge -1.
e.) AlCl3 has 1 aluminum ion with the charge +3 and
3 chloride ions each with the charge -1.
hope this helps~ (plz mark brainliest Sam Dover)