Question

what is the inverse of the given relation

y=7x^2-3

a. y= +/- sqrt x+3/7
b. x= sqrt y+3/7
c. y^2 = x+3/7
d. y= +/- sqrt x-3/7

Answer 1

Answer:

A

Step-by-step explanation:

To find the inverse, we will follow the steps below:

1. Interchange x and y

2. solve for new y

Hence,

$y=7x^2 - 3\\x=7y^2-3\\x+3=7y^2\\\frac{x+3}{7}=y^2\\+-\sqrt{\frac{x+3}{7}} =y$

Answer is  $y=+-\sqrt{\frac{x+3}{7}}$

Answer choice A is right.

Answer 2

Answer:

y= +/- sqrt x+3/7